1761A - Two Permutations - CodeForces Solution

brute force constructive algorithms

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Python Code: 

t = int(input())
for _ in range(t):
  n,a,b = map(int,input().split())
  if a+b<=n-2 or (a==b and a==n):
    print("Yes")
  else:
    print("No")

C++ Code: 

#include <bits/stdc++.h>
using namespace std;
#define ll long long int
ll sol()
{
    ll n,a,b;
    cin>>n>>a>>b;
    if(a==b && n==b)
    {
        cout<<"Yes"<<endl;
         return 0;
    }
    else
    {
        if(n-a-b>1)
        {
            cout<<"Yes"<<endl;
             return 0;
        }
        else{
            cout<<"No"<<endl;
             return 0;
        }

    }
    return 0;
}

int main()
{
    ll t;
    cin>>t;
    while(t--)
    {
        ll a=sol();

    }
}


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